Oct 2016 updated: Actualtests Cisco 200-125 training 141-150

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2016 Oct 200-125 test

Q141. - (Topic 9) 

Which two statements about the tunnel mode ipv6ip command are true? (Choose two.) 

A. It enables the transmission of IPv6 packets within the configured tunnel. 

B. It specifies IPv4 as the encapsulation protocol. 

C. It specifies IPv6 as the encapsulation protocol. 

D. It specifies IPv6 as the transport protocol. 

E. It specifies that the tunnel is a Teredo tunnel. 

Answer: A,B 


Q142. - (Topic 8) 

It has become necessary to configure an existing serial interface to accept a second Frame Relay virtual circuit. Which of the following procedures are required to accomplish this task? (Choose three.) 

A. Remove the IP address from the physical interface. 

B. Encapsulate the physical interface with multipoint PPP. 

C. Create the virtual interfaces with the interface command. 

D. Configure each subinterface with its own IP address. 

E. Disable split horizon to prevent routing loops between the subinterface networks. 

F. Configure static Frame Relay map entries for each subinterface network. 

Answer: A,C,D 


Q143. - (Topic 8) 

Which encapsulation type is a Frame Relay encapsulation type that is supported by Cisco routers? 

A. IETF 

B. ANSI Annex D 

C. Q9333-A Annex A 

D. HDLC 

Answer: A 


Q144. CORRECT TEXT - (Topic 7) 

A network associate is configuring a router for the weaver company to provide internet access. The ISP has provided the company six public IP addresses of 198.18.184.105 

198.18.184.110. The company has 14 hosts that need to access the internet simultaneously. The hosts in the company LAN have been assigned private space addresses in the range of 192.168.100.17 – 192.168.100.30. 


Answer: The company has 14 hosts that need to access the internet simultaneously but we just have 6 public IP addresses from 198.18.184.105 to 198.18.184.110/29. 

Therefore we have to use NAT overload (or PAT) 

Double click on the Weaver router to open it 

Router>enable Router#configure terminal 

First you should change the router's name to Weaver 

Router(config)#hostname Weaver 

Create a NAT pool of global addresses to be allocated with their netmask. 

Weaver(config)#ip nat pool mypool 198.18.184.105 198.18.184.110 netmask 255.255.255.248 

Create a standard access control list that permits the addresses that are to be translated 

Weaver(config)#access-list 1 permit 192.168.100.16 0.0.0.15 

Establish dynamic source translation, specifying the access list that was defined in the prior step 

Weaver(config)#ip nat inside source list 1 pool mypool overload 

This command translates all source addresses that pass access list 1, which means a source address from 192.168.100.17 to 192.168.100.30, into an address from the pool named mypool (the pool contains addresses from 198.18.184.105 to 198.18.184.110) 

Overload keyword allows to map multiple IP addresses to a single registered IP address (many-to-one) by using different ports 

The question said that appropriate interfaces have been configured for NAT inside and NAT outside statements. 

This is how to configure the NAT inside and NAT outside, just for your understanding: 

Weaver(config)#interface fa0/0 

Weaver(config-if)#ip nat inside 

Weaver(config-if)#exit 

Weaver(config)#interface s0/0 

Weaver(config-if)#ip nat outside 

Weaver(config-if)#end 

Finally, we should save all your work with the following command: 

Weaver#copy running-config startup-config 

Check your configuration by going to "Host for testing" and type: 

C :\>ping 192.0.2.114 

The ping should work well and you will be replied from 192.0.2.114 


Q145. - (Topic 3) 

You have been asked to come up with a subnet mask that will allow all three web servers to be on the same network while providing the maximum number of subnets. Which network address and subnet mask meet this requirement? 

A. 192.168.252.0 255.255.255.252 

B. 192.168.252.8 255.255.255.248 

C. 192.168.252.8 255.255.255.252 

D. 192.168.252.16 255.255.255.240 

E. 192.168.252.16 255.255.255.252 

Answer: B 


200-125 test

Up to the minute 200-125 exam question:

Q146. - (Topic 4) 

A router has learned three possible routes that could be used to reach a destination network. One route is from EIGRP and has a composite metric of 20514560. Another route is from OSPF with a metric of 782. The last is from RIPv2 and has a metric of 4. Which route or routes will the router install in the routing table? 

A. the OSPF route 

B. the EIGRP route 

C. the RIPv2 route 

D. all three routes 

E. the OSPF and RIPv2 routes 

Answer: B 


Q147. - (Topic 2) 

Cisco Catalyst switches CAT1 and CAT2 have a connection between them using ports FA0/13. An 802.1Q trunk is configured between the two switches. On CAT1, VLAN 10 is chosen as native, but on CAT2 the native VLAN is not specified. 

What will happen in this scenario? 

A. 802.1Q giants frames could saturate the link. 

B. VLAN 10 on CAT1 and VLAN 1 on CAT2 will send untagged frames. 

C. A native VLAN mismatch error message will appear. 

D. VLAN 10 on CAT1 and VLAN 1 on CAT2 will send tagged frames. 

Answer: C 


Q148. - (Topic 7) 

Scenario 

Refer to the topology. Your company has decided to connect the main office with three other remote branch offices using point-to-point serial links. 

You are required to troubleshoot and resolve OSPF neighbor adjacency issues between the main office and the routers located in the remote branch offices. 









An OSPF neighbor adjacency is not formed between R3 in the main office and R5 in the Branch2 office. What is causing the problem? 

A. There is an area ID mismatch. 

B. There is a PPP authentication issue; a password mismatch. 

C. There is an OSPF hello and dead interval mismatch. 

D. There is a missing network command in the OSPF process on R5. 

Answer: C 


Q149. - (Topic 4) 

Refer to the exhibit. 


What is the meaning of the output MTU 1500 bytes? 

A. The maximum number of bytes that can traverse this interface per second is 1500. 

B. The minimum segment size that can traverse this interface is 1500 bytes. 

C. The maximum segment size that can traverse this interface is 1500 bytes. 

D. The minimum packet size that can traverse this interface is 1500 bytes. 

E. The maximum packet size that can traverse this interface is 1500 bytes. 

F. The maximum frame size that can traverse this interface is 1500 bytes. 

Answer: E 


Q150. - (Topic 1) 

Which of the following statements describe the network shown in the graphic? (Choose two.) 


A. There are two broadcast domains in the network. 

B. There are four broadcast domains in the network. 

C. There are six broadcast domains in the network. 

D. There are four collision domains in the network. 

E. There are five collision domains in the network. 

F. There are seven collision domains in the network. 

Answer: A,F 


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